Depending on the parameters, your equation has a variable number of solutions:

TP[x_] = 
 pr/x  ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + y  g)))^(1/(1 - 
         b)) - ((c + 1)  (Kr/x + Kp/(n  x) + 
       Kf/(n  x) + (hr + g)/
         x  (2  x  (-((a  (-1 + b)  g  x^2  y)/(L + g  L  y)))^(1/(1 -
                b))) + (hp + 
           g)/(2  R  x)  ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + 
               y  g)))^(2/(1 - b)) + ((hp + g)  (n - 
             1))/(2  x)  ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + 
               y  g)))^(2/(1 - 
             b))  (x  ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + 
                  y  g)))^(1/(1 - b)) - 1/R) + 
       1/x^2  S + (v/x + 
          vp/(n  x))  ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + 
               y  g)))^(1/(1 - b)) + 
       1/(n  x)^2  Sv + (Pv  w)/(x  f  ww)  ((a  (1 - 
                b)  (x^2))/(2  L)  ((y  g)/(1 + y  g)))^(1/(1 - 
             b)) + (((cf  f) + (m  bk))/(x  f  ww)  (k  n  x + 
           k/q  (Log[1 + z  E^(-q  n  x)] - 
              Log[1 + z]))))) + (c  ((pp/x + 
         pf/x)  ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + 
              y  g)))^(1/(1 - b)))) + (pr/
       x  l  (2  a  g  (x^2)  y  (((-((a  (-1 + b)  g  x^2  y)/(L + 
                   g  L  y)))^(1/(1 - b)))^b))/(L + 
         g  L  y) - ((a  (1 - b)  (x^2))/(2  L)  ((y  g)/(1 + 
             y  g)))^(1/(1 - b))  (M - x)) // Simplify
(*Compute the first derivative*)
dTPdx = D[TP[x], x] // Simplify;
effe = Block[{a = 1, b = 2, bk = 1, c = 1, cf = 4, f = 1, g = 1, 
   hp = 1, hr = 1, k = 1, Kf = 1, Kp = 1, Kr = 1, l = 1, L = 1, m = 1,
    M = 1, n = 1, pf = 1, pp = 1, pr = 1, Pv = 1, q = 1, R = 1, S = 1,
    Sv = 1, v = 1, vp = 1, w = 1, ww = 1, y = 1, z = 1},
  dTPdx]
Plot[effe, {x, -10, 10}, PlotRange -> {-1, 1}]
Solve[effe == 0, x, Reals]
gi = Block[{a = 1, b = 0, bk = 1, c = 1, cf = 4, f = 1, g = 1, hp = 1,
    hr = 1, k = 1, Kf = 1, Kp = 1, Kr = 1, l = 1, L = 1, m = 1, M = 1,
    n = 1, pf = 1, pp = 1, pr = 1, Pv = 1, q = 1, R = 1, S = 1, 
   Sv = 1, v = 1, vp = 1, w = 1, ww = 1, y = 1, z = 1},
  dTPdx]
Plot[gi, {x, -10, 10}, PlotRange -> {-1, 1}]
Solve[gi == 0, x, Reals]
acca = Block[{a = 4, b = 2, bk = 1, c = 1, cf = 4, f = 3, g = 2, 
   hp = 1, hr = 1, k = 1, Kf = 2, Kp = 1, Kr = 5, l = 3, L = 1, m = 1,
    M = 1, n = 1, pf = 4, pp = 1, pr = 1, Pv = 1, q = 1, R = 10, 
   S = 1, Sv = 1, v = 1, vp = 1, w = 1, ww = 1, y = 1, z = 2},
  dTPdx]
Plot[acca, {x, -10, 10}]
Solve[acca == 0, x, Reals]

You cannot expect a simple analytical solution for the general case.