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bug in ListPlot3D ex) ListPlot3D[{{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}]

This function does not work under this kind of points below. I think it should be plotted triangular mesh, but It doesn't work... Is it bug? Is there any solution?

(Example:)

 ListPlot3D[{{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}]

(version of mathematica is 9.0.1.0)
POSTED BY: ohshima taisuke
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Hi,

I don't think that it would do that. The documentation says

enter image description here

The last two points in {{1, 1, 1}, {0, 1, 0}, {0, 1, 1}} have the same x/y coordinates but different values for z. If you modify your input so that it reads 

ListPlot3D[{{1, 1, 1}, {0, 1/5, 0}, {0, 1, 1}}, PlotStyle -> Thick]

it shows a result.

enter image description here

If you want the two last points to have at nearly the same y coordinate 

ListPlot3D[{{1, 1, 1}, {0, 0.99, 0}, {0, 1, 1}}, PlotRange -> {{0, 1}, {0, 1}, {0, 1}}]

Cheers,

Marco
POSTED BY: Marco Thiel
David Keith
David Keith
Posted 11 years ago

If you are looking to plot the points as independent locations, or the triangle defined by them, you could try these functions:

In[1]:= points = {{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}

Out[1]= {{1, 1, 1}, {0, 1, 0}, {0, 1, 1}}

In[2]:= ListPointPlot3D[points]

In[3]:= Polygon[points] // Graphics3D
POSTED BY: David Keith
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