Message Boards Message Boards

11 Replies
11 Total Likes
View groups...
Share this post:

How to run Johansen test in Mathematica

Posted 11 years ago

Does anyone have any idea on wether it's possible to run the Johansen Cointegration tests in Mathematica? If not, is the code available somewhere?

POSTED BY: Xavier Vallee
11 Replies
You may quickly take a look at this link:
POSTED BY: Shenghui Yang
Posted 11 years ago
Thanks Shenghui. I've tried this piece of code but it doesn't seem to work on Mathematica 9.
POSTED BY: Xavier Vallee
Could you please post some results here or error message? 
POSTED BY: Shenghui Yang
Posted 11 years ago
I am trying to test the cointegration between two ETFs.
 ewa = FinancialData["NYSE:EWA", {{2006, 4, 4}, {2012, 4, 9}}, "Value"];
 ewc = FinancialData["NYSE:EWC", {{2006, 4, 4}, {2012, 4, 9}}, "Value"];
 data = Transpose@{ewa, ewc};
 johansenProcedure[levels_?MatrixQ, p_Integer] /;
 (Dimensions[levels][[ 1]] > (Dimensions[levels][[2]] + p)) :=
 With[{N = Dimensions[levels][[1]], T = Dimensions[levels][[2]],
 diff = Rest[levels - RotateLeft[levels]], ypt = Drop[levels, -p]},
 Module[{x, r0t, rpt, s00, sop, cc, \[Lambda], v\[Lambda], log\[Lambda]},
x = Join @@ (Drop[RotateLeft[diff, #], p - 1] & /@ Range[p]);
With[{q = Inverse[Transpose[x].x], y0t = Drop[diff, p - 1]},
r0t = y0t - x.q.Transpose[x].y0t; rpt = ypt - x.q.Transpose[x].ypt; s00 = (Transpose[r0t].r0t)/T; s0p = (Transpose[r0t].rpt)/T;
cc = Inverse[CholeskyDecomposition[(Transpose[rpt].rpt)/T]];
{\[Lambda], v\[Lambda]} = Eigensystem[(cc.Transpose[s0p].Inverse[s00].s0p.Transpose[cc])];
log\[Lambda] = Log[1 - \[Lambda]];
{Reverse[-T* FoldList[Plus, First[log\[Lambda]], Rest[log\[Lambda]]]],
Reverse[-T log\[Lambda]], Join[Reverse[Transpose[Transpose[cc].v\[Lambda]]], s00, s0p]} ]]];

johansenProcedure[data, 10]
and then it keeps running until I abort
Dot::dotsh: Tensors {<<1>>} and {{0.38,0.42},{-0.21,-0.27},{0.03,0.13},{0.,-0.03},<<44>>,{0.04,0.02},{-0.56,-0.63},<<1455>>} have incompatible shapes. >>
POSTED BY: Xavier Vallee

Usually if you have error message from your function, the best way to debug is to break a block of codes into separated cells. In your case, I notice this line is broken: 
r0t = y0t - x.q.Transpose[x].y0t;
rpt = ypt - x.q.Transpose[x].ypt;
The dimensional mismatch is from here. 
POSTED BY: Shenghui Yang
Posted 11 years ago
thanks. Found the problem and it seems to work now.
POSTED BY: Xavier Vallee
Posted 11 years ago
If you got it to work, could you uplode the working code?
Posted 11 years ago
I'm the owner of the website Shenghui linked to. If there are any changes needed to be made to that code, please let me know at the email address on the web site. It is more than ten years since I posted that code and I have not had time to check which of those notebooks still work in version 9. I think I was using version 3 or 4 when I posted all that code. And as I said under the link to that notebook: "I translated the algorithm from Gauss. Untested. Use at your own risk! "
POSTED BY: Luci Ellis
Posted 11 years ago
Could you post the code after the fix? 
Posted 11 years ago
Thank you for posting this and related discussion on MSE, Luci, it is really appreciated.
POSTED BY: Vitaliy Kaurov
Reply to this discussion
Community posts can be styled and formatted using the Markdown syntax.
Reply Preview
or Discard

Group Abstract Group Abstract