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Daqing Li, consider FullSimplify[(x - 5)/Sqrt[x - 5]] (*Sqrt[-5 + x]*)
I like the following result. a = Cos[Pi/3] + I*Sin[Pi/3]; a^Range[3, 99, 3] // FullSimplify (* {-1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1, 1, -1}*)
(Pi/2 - E I) - NSum[(I)^n *((-n)^(1/n) - 1), {n, 1, Infinity}, WorkingPrecision -> 30, Method -> "AlternatingSigns"] + ( 3^(3/4) Sqrt[19 - 5^(2/3)])/10^3 + Im[(23 + 9*I)^(3/19)/10] I = -1.956013164857547142...
There are several ways of getting that extra digit. Perhaps you could try ScientificForm[1.23001`4, 4]
Like me, I'm sure others are checking to see if that problem exists on their setup too. My Windows 10 system doesn't have that problem.
How is this? plot (1.2 + i y - 1)^2)/(y + 1/2 i) from y = -100 to 100 ![enter image description here][1] [1]: https://community.wolfram.com//c/portal/getImageAttachment?filename=6758Capture.JPG&userId=366611
Nick Arnold: Try Gianluca Gorni's input. I must have forgot that there was a standard solution for Integrate[g'[x]/g[x], x] .
Do the examples in the documentation work?
10,000 digits of $nul = -0.0760867...,$ the hard to calculate nul, not necessarily $ \sum _{m=2}^{\infty } (-1)^m \left( \eta ^{(m)}(m)\right)=-0.0724829...?.$ m = NSum[(-1)^n (n^(1/n) - 1), {n, 1, Infinity}, Method ->...
BTW, I looked up a former physics teacher who gave me a good interview concerning her writing in the sciences. I got a good grade on my paper about the interview and in the class. Thank you all for your consideration! Perhaps I was a little to...