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LaplaceTransform[y''[t] - 2 y'[t] + y[t] == 1 + t, t, s] /. {y[0] -> 1, y'[0] -> 0} I get LaplaceTransform[ y[t] - 2 Derivative[1][y][t] + (y^\[Prime]\[Prime])[t], t, s] == 1/s^2 + 1/s
This is okay. Animate[Plot3D[h x^2 y, {x, -1, 1}, {y, -1, 1}, PlotRange -> 2, Background -> Blue], {h, 0, 1, .01}] But I want a background, in the animation, same the picture in the file attachment. Is it possible?
Thank you for your help. How should I understand VertexTextureCoordinates? pic = ExampleData[{"TestImage", "House"}]; ![enter image description here][1] V = {{0, Sqrt[3]/2, 1/2}, {0, Sqrt[3]/2, -(1/2)}, {0, 0, -1}, {0,...
Why does this not work? ParametricPlot3D[{t, t, t}, {t, 0, 3}, PlotStyle -> {If[1
(* This works *) anima = False; Button["Iniciar/Detener", If[anima, anima = False, anima = True]; Print[anima]] (* But this does not work *) anima = False; Button["Iniciar/Detener", If[anima, anima = False, anima =...
Why InverseLaplaceTransform[ArcTan[1/s], s, t] `Out[]= Sin[t]/t` works and InverseLaplaceTransform[ArcTan[s], s, t] does not work?
Graphics[Arrow[Circle[{0, 0}, 1, {Pi/4, 3 Pi/4}]]]