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| The outter List layer of your data was giving FindFit some heartburn. I had to remove that with First. The result of FindFit is replacement rules of the form {R1 -> val1, R2 -> val2, R3 -> val3, ...}. These rules will directly replace the matching... |
| Plot can take all three solutions at the same time. In this example Chop helps by filtering out small complex components.[mcode]Manipulate[ s = Solve[A == (1/(1 - Exp[EA]*x)^2 + B*Exp[y]/(1 + x*Exp[y]))*x, x]; Plot[Chop[x /. s], {y, 0, 15},... |
| Wondering if M10 will have anything in it for these mixed linear models. |
| Check DownValues[myCHcc] to see how many different definitions you have created. You will find that the input myCHcc[1] is being intercepted by the one with the pattern _Integer before getting to the one with Conditional /;. By reusing the same... |
| Include the Quantity wrapper around t in the integrand. [mcode]In[ ]:= Integrate[Quantity[5, "Meters"/"Seconds"^2]*Quantity[t, "Minutes"], {Quantity[t, "Minutes"], Quantity[0, "Seconds"], Quantity[10, "Seconds"]}] Out[ ]= Quantity[250, "Meters"]... |
| Claire Danes was in the 1998 (Liam Neeson) version and Anne Hathaway was in the 2012 (Hugh Jackman) version of Les Mis. That's not a link. Check the films Romeo+Juliet and The Odd Life of Timothy Green, ... |
| You are absolutly correct in the observation, that the generic variable # inside (# + # &) has no way of knowing the first # comes from the outside Map and the second # comes from the inside Map. This inside and outside indexing is already handeled... |
| Give the location of centers of the vectors to be drawn to VectorPlot3D using VectorPoints option as a list of points.[mcode]points = Join @@ Table[{i, j, .5}, {i, -1, 1, .25}, {j, -1, 1, .25}]; VectorPlot3D[{0, 0, Cos[x] Cos[y]}, {x, -\[Pi]/2,... |
| With is used to inject a value into an expression, then releases it. Handy for building up arguments inside HoldAll functions like Plot.plotCurves[n_] := With[{b = bounds[[n]]}, Plot[curves[[n]], b]] This version inserts both values,... |
| Check this result make sure it fits all the boundary cases you where expecting:[code]T = Ki = 0; i = 0; While[i |