User Portlet
| Discussions |
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| Hi; How can I view a cell in a different notebook. In my case, I have information in cells of a notebook that is common to several notebooks. Instead of permanently placing this information (copying) this information each individual notebook, I... |
| Hi Arben; Actually, I copied the function directly from the documentation (possibly the 1st entry in the examples) and was just wondering how to convert it into the abbreviated form. Thanks, Mitch Sandlin |
| Thanks, Restarting the session did the job. Mitch Sandlin |
| Hi Doug; Following your advice, I deleted my data from my SparseArray[] and moved it into a field named dta1= {{1,5}-> 1, etc.}}. Then loaded the data into the functions: MatrixPlot[SparseArray[dta1,{20,20}]] The new configuration gave me... |
| Is there a Repository (Neural Net) to identify trees and plants? Thanks, Mitch Sandlibn |
| Hi When extracting coefficients using patterns, I am having problems when the coefficient is 1 - see attached notebook. It appears that the coefficient of 1 is being ignored completed and instead the unknown is being selected. &[Wolfram... |
| What is the best way to visualize, by way of a plot, the output of the Series[] function (For example function - Series[E^x, {x, 0, 5}] )? Additionally, is it possible to display the denominators of the output as factorials instead of expanded? ... |
| Thanks for the quick and thorough explanation - it is a great help. I have a couple of other minor questions. Why is there a short segment of red line in the solution and does it mean anything? Secondly, how did you come up with the values of... |
| Hi Rohit; I included your NestList[] iterator into my Graphics[] function replacing the points (P1, P2, P3, and P4) which I had created manually and your code worked great in duplicating what I had created manually. However, the location of... |
| Hi Neil; Thank you so much for your response, it answered my question exactly. If I wanted to take the visualization up a notch and visualize the solution in both 2D and 3D, would the attached be a correct solution? Since I followed your... |