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| Thanks so much. I also found that Reduce[] works real well also. Additionally you do not need to suffix // DeleteDuplicates to the Reduce[] expression. Thanks again, Mitch Sandlin |
| Hi Murray; I tried duplicating your example, but did not get the same results. Please see attached notebook and give me your thoughts. Thanks so much, Mitch Sandlin |
| The one attached below - GradWork01. Not sure what happened to the one that I attached earlier. Thanks so much for reviewing this. Mitch Sandlin |
| Hi; I really like using the "D" Command because of its format and ease of use, however the command seems to cause me calculation problems - See Attached. I defined the function f[x_,y_] and used the function to generate derivatives for both x... |
| Thanks so much for your reply. I was under the impression that D was a shortcut for Derivative, which is apparently not the case. However there seems to still be a problem with D[f[1, 1], x] and D[f[1, 1], y], since it still gave me an answer... |
| Hi Christos; Knowing what the function is equal to is part of the problem. It is actually equal to 5 but you don't know that until you complete the squares. Once you know the function equals 5, you can plug the function into Solve[] and get the... |
| Hi; When I key the following code into a notebook: Solve[8/Sin[36 Degree] == 5/[Beta],[Beta], Reals] // N ArcSin[0.3674 Degree] I get 0.00641238 for the answer to the 2nd line - see attached, which according to my TI-89 is... |
| Hi From what I can tell, it seems that you are exactly right that the only input allowed is Cartesian. Is it possible to embed the TransformedField[ ] (or some other function) into the Point, Line, Arrow functions to increase the coordinate... |
| Hi, Is it possible to directly embed functions such as (Grad, Div & Curl) directly into plot commands? For example: VectorPlot3D[ Grad[{E^x Cos[y], E^x Sin[y], z}, {x, y, z}], {x, 0, 3}, {y, 0, 3}, {z, 0, 3}] Thanks, ... |
| When using DSolve or DSolveValue in calculating a solution for y + 5y == 0, I am getting the answer of C1 -1/5 e^(-5x) + C2 see attached. I have solved this equation several different ways using different methods without generating the -1/5... |