User Portlet
| Discussions |
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| What is the best way to visualize, by way of a plot, the output of the Series[] function (For example function - Series[E^x, {x, 0, 5}] )? Additionally, is it possible to display the denominators of the output as factorials instead of expanded? ... |
| Thanks for the quick and thorough explanation - it is a great help. I have a couple of other minor questions. Why is there a short segment of red line in the solution and does it mean anything? Secondly, how did you come up with the values of... |
| Hi Rohit; I included your NestList[] iterator into my Graphics[] function replacing the points (P1, P2, P3, and P4) which I had created manually and your code worked great in duplicating what I had created manually. However, the location of... |
| Hi Neil; Thank you so much for your response, it answered my question exactly. If I wanted to take the visualization up a notch and visualize the solution in both 2D and 3D, would the attached be a correct solution? Since I followed your... |
| Hi; Please see attached notebook detailing confusion taking the partial derivative of y' with respect to y. In my way of thinking (which may be wrong) y' and y are totally different and therefore y' should be considered a constant when taking the... |
| Hi Gianluca; I have done quite a bit of research today and believe that you are exactly right. Thanks so much for your help, Mitchell Sandlin |
| Hi; In working with StreamPlot and Vector Plot, I am getting two different representations - see attached. It appears that Vector Plot is representing expected results whereas StreamPlot seems to be having problems, which I cannot figure out.... |
| I am creating a user defined function f[t_] := where I am evaluating an integral in the body of the function without any issues. I can subsequently evaluate the user function f[t] and obtain the correct answer. However, when I plot the expression... |
| My goal is to display the inverse trigonometric function of ArcCos and Cos through a specific x range of 0 to Pi for Cos and -1 to 1 for the ArcCos since those domain ranges will pass the horizontal line test as being one-to-one and thus inverses... |
| Hi; In calculating an integral (using both the icon from the Classroom Pallett and the Integrate[] function in Mathematica) , it appears that Mathematica is placing an additional value in the results that is both unexpected and unwanted (see... |