In[1]:= 2^2 (22 + 22^2)
Out[1]= 2024

Not quite a one-liner in this form, but 2024 is the 22nd tetrahedral number.

tet = {{-11, -11, 11}, {-11, 11, -11}, {11, -11, -11}, {11, 11, 11}};
pick = Select[Tuples[Range[-12, 12], {3}], 
   OddQ[Total[#]] && Total[#] != -11 && 
     Min[ResourceFunction["Areal"][tet, #]] >= 0 &];
Graphics3D[Sphere[#, 1/Sqrt[2]] & /@ pick, Boxed -> False]

Here's a check:

 Total[Table[n  (n + 1)/2, {n, 1, 22}]]

Fun with hyberbolic cosines:

Cosh[3  ArcCosh[8]]

Fun with squares

{64, 24}^2    {4096, 576}
2024^2          4096576

Perhaps a few more things can be found here:

Mathematical Beauties of the Happy New Year 2024

https://math1089.in/2023/12/30/mathematical-beauties-of-the-happy-new-year-2024

Slight revision of the count down one I saw last year that someone else (not sure who to credit as it wasn't me): https://www.wolframalpha.com/input?i=%2810+%2B+%289+%2B8+%C3%97+7%29+%C3%97+6%29+%C3%97+5+%2B+4+%C3%97+3+%C3%97+2+%C3%97+1

Changed the minus one at the end (which returned 2023) to multiply by one and you get 2024. Remember for next year, it can be plus one at the end to get 2025 when that is relevant!